The MATLAB hsv colormap uses hsv2rgb() where hue is a linear ramp from 0 to 1, and saturation and value are all 1's. As H(:,3) varies from 0 to 1, the brightness increases. When H(:,2) is 1, the colors are fully saturated (i.e., they contain no white component). When H(:,2) is 0, the colors are unsaturated (i.e., shades of gray). RGB is returned as an m-by-n-by-3 image array whose three planes contain the red, green, and blue components for the image.Īs H(:,1) varies from 0 to 1, the resulting color varies from red through yellow, green, cyan, blue, and magenta, and returns to red. HSV is an m-by-n-by-3 image array whose three planes contain the hue, saturation, and value components for the image. Its columns are intensities of red, green, and blue, respectively.Ĭonverts the HSV image to the equivalent RGB image. The columns of H represent hue, saturation, and value, respectively. H is an m-by-3 matrix, where m is the number of colors in the colormap. Imwrite(srgbImage, 'srgbImage.png') % Save image for testing.Hsv2rgb (MATLAB Functions) MATLAB Function ReferenceĬonverts a hue-saturation-value (HSV) colormap to a red-green-blue (RGB) colormap. SrgbImage = im2uint8(srgbImage) % Convert from double in range to uint8 in range (optional). SrgbImage = lin2rgb(rgbImage) % Apply Gamma correction.įigure imshow(srgbImage) title('srgbImage') impixelinfo RgbImage = rgbImage / max(rgbImage(:)) % Convert to range įigure imshow(rgbImage) title('rgbImage') impixelinfo RgbImage = cat(3, Red, Green, Blue) % Concatenate Red, Green and Blue channels. The RGB image looks dark, probably because the images are captured without Gamma correction.įor applying Gamma correction, according to sRGB standard, we may use lin2rgb function: srgbImage = lin2rgb(rgbImage) įigure imshow(Blue, ) title('Blue') impixelinfoįigure imshow(Green, ) title('Green') impixelinfoįigure imshow(Red, ) title('Red') impixelinfo When showing a single channel image as Grayscale, we may use imshow(I, ).įor inspecting pixel values, we may add impixelinfo after imshow (we may also add a title): figure What is the point I don't understand here? Is there a solution? You can find that PaviaU.mat file with the variable inside as paviaU through this link PaviaU.matĪs commented, in MATLAB the range of RGB images should be (for type double).ĭividing by the maximum value is a simple way for converting the range to (assuming input pixels are positive). However, I think, inside the library of image processing there is a file with the name of paviaU.dat that file works, and inside the App, I observed the spectrum and played with it. I want to read this into MATLAB, convert it to RGB24 format, and output the image. mat file on the App section of Matlab where there is a hyperspectral image app, I could not observe the spectrum because band information was absent. 7 I am getting an RGB matrix from a microprocessor that outputs an image in RGB565 format. When I use imagesc(Red) instead of imshow I see pictures as a result, but it is not what I would like to see. Imagesc(newBlue) %*this line gives the result as a scaled image* I used different codes, searched forums etc. The one who gave me this question to solve, described it as something very basic, however, I am having a very difficult time with it. It is a hyperspectral image and it has 103 bands opposite to the normal RGB image which contains just 3. I have a problem with extracting 3 bands under the names R, G, and B, and then using those bands as 3 colour channels for RGB pictures.
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